Base | Representation |
---|---|
bin | 110001011001011110… |
… | …011101010110110101 |
3 | 12001220111120000010101 |
4 | 301121132131112311 |
5 | 1332111413424331 |
6 | 40211103354101 |
7 | 3555254025625 |
oct | 613136352665 |
9 | 161814500111 |
10 | 53040764341 |
11 | 20549146334 |
12 | a3432b2931 |
13 | 5003a27976 |
14 | 27d2508885 |
15 | 15a67dc061 |
hex | c5979d5b5 |
53040764341 has 2 divisors, whose sum is σ = 53040764342. Its totient is φ = 53040764340.
The previous prime is 53040764323. The next prime is 53040764377. The reversal of 53040764341 is 14346704035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34464437316 + 18576327025 = 185646^2 + 136295^2 .
It is a cyclic number.
It is not a de Polignac number, because 53040764341 - 27 = 53040764213 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53040764341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53040764311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26520382170 + 26520382171.
It is an arithmetic number, because the mean of its divisors is an integer number (26520382171).
Almost surely, 253040764341 is an apocalyptic number.
It is an amenable number.
53040764341 is a deficient number, since it is larger than the sum of its proper divisors (1).
53040764341 is an equidigital number, since it uses as much as digits as its factorization.
53040764341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 53040764341 in words is "fifty-three billion, forty million, seven hundred sixty-four thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •