Base | Representation |
---|---|
bin | 1111011011111111001… |
… | …10000100111101010111 |
3 | 1212201002222221110002221 |
4 | 13231333212010331113 |
5 | 32142300421244443 |
6 | 1043401121043211 |
7 | 53215225524133 |
oct | 7557746047527 |
9 | 1781088843087 |
10 | 530421665623 |
11 | 194a50225113 |
12 | 86971186507 |
13 | 3b03199ba55 |
14 | 1b95b6723c3 |
15 | dbe679eeed |
hex | 7b7f984f57 |
530421665623 has 2 divisors, whose sum is σ = 530421665624. Its totient is φ = 530421665622.
The previous prime is 530421665593. The next prime is 530421665647. The reversal of 530421665623 is 326566124035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530421665623 - 237 = 392982712151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530421665623.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530421665663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265210832811 + 265210832812.
It is an arithmetic number, because the mean of its divisors is an integer number (265210832812).
Almost surely, 2530421665623 is an apocalyptic number.
530421665623 is a deficient number, since it is larger than the sum of its proper divisors (1).
530421665623 is an equidigital number, since it uses as much as digits as its factorization.
530421665623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 43.
Adding to 530421665623 its reverse (326566124035), we get a palindrome (856987789658).
The spelling of 530421665623 in words is "five hundred thirty billion, four hundred twenty-one million, six hundred sixty-five thousand, six hundred twenty-three".
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