Base | Representation |
---|---|
bin | 1001111000010100… |
… | …00000100100100011 |
3 | 111200122211111111001 |
4 | 10330022000210203 |
5 | 41330340132120 |
6 | 2234155532431 |
7 | 245305106005 |
oct | 47412004443 |
9 | 14618744431 |
10 | 5304224035 |
11 | 2282107030 |
12 | 104045a117 |
13 | 666ba8206 |
14 | 384654375 |
15 | 2109ebe0a |
hex | 13c280923 |
5304224035 has 16 divisors (see below), whose sum is σ = 6949232640. Its totient is φ = 3854550240.
The previous prime is 5304224017. The next prime is 5304224039.
5304224035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5304224035 - 221 = 5302126883 is a prime.
It is a super-2 number, since 2×53042240352 = 56269585226943362450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5304223994 and 5304224012.
It is not an unprimeable number, because it can be changed into a prime (5304224039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32644 + ... + 108046.
It is an arithmetic number, because the mean of its divisors is an integer number (434327040).
Almost surely, 25304224035 is an apocalyptic number.
5304224035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5304224035 is a deficient number, since it is larger than the sum of its proper divisors (1645008605).
5304224035 is a wasteful number, since it uses less digits than its factorization.
5304224035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76698.
The product of its (nonzero) digits is 14400, while the sum is 28.
The square root of 5304224035 is about 72830.1039062831. The cubic root of 5304224035 is about 1743.9764645344.
It can be divided in two parts, 53042 and 24035, that added together give a palindrome (77077).
The spelling of 5304224035 in words is "five billion, three hundred four million, two hundred twenty-four thousand, thirty-five".
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