Base | Representation |
---|---|
bin | 1111011011111111100… |
… | …11111111001101110011 |
3 | 1212201010020210201011012 |
4 | 13231333303333031303 |
5 | 32142302334441430 |
6 | 1043401331141135 |
7 | 53215301522246 |
oct | 7557763771563 |
9 | 1781106721135 |
10 | 530425312115 |
11 | 194a52295846 |
12 | 869724447ab |
13 | 3b03267773a |
14 | 1b95bd4125d |
15 | dbe6c70695 |
hex | 7b7fcff373 |
530425312115 has 4 divisors (see below), whose sum is σ = 636510374544. Its totient is φ = 424340249688.
The previous prime is 530425312073. The next prime is 530425312117. The reversal of 530425312115 is 511213524035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530425312115 - 26 = 530425312051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530425312117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53042531207 + ... + 53042531216.
It is an arithmetic number, because the mean of its divisors is an integer number (159127593636).
Almost surely, 2530425312115 is an apocalyptic number.
530425312115 is a deficient number, since it is larger than the sum of its proper divisors (106085062429).
530425312115 is a wasteful number, since it uses less digits than its factorization.
530425312115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106085062428.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 530425312115 in words is "five hundred thirty billion, four hundred twenty-five million, three hundred twelve thousand, one hundred fifteen".
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