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530433254155 = 5715155235833
BaseRepresentation
bin1111011100000000100…
…10010010001100001011
31212201010210202012120211
413232000102102030023
532142311403113110
61043402213301551
753215426161010
oct7560022221413
91781123665524
10530433254155
11194a5681a812
12869750348b7
133b0341c867c
141b95d00b707
15dbe77dd98a
hex7b8049230b

530433254155 has 8 divisors (see below), whose sum is σ = 727451320032. Its totient is φ = 363725659968.

The previous prime is 530433254149. The next prime is 530433254161. The reversal of 530433254155 is 551452334035.

It is an interprime number because it is at equal distance from previous prime (530433254149) and next prime (530433254161).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 530433254155 - 223 = 530424865547 is a prime.

It is a super-2 number, since 2×5304332541552 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7577617882 + ... + 7577617951.

It is an arithmetic number, because the mean of its divisors is an integer number (90931415004).

Almost surely, 2530433254155 is an apocalyptic number.

530433254155 is a deficient number, since it is larger than the sum of its proper divisors (197018065877).

530433254155 is a wasteful number, since it uses less digits than its factorization.

530433254155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15155235845.

The product of its (nonzero) digits is 540000, while the sum is 40.

The spelling of 530433254155 in words is "five hundred thirty billion, four hundred thirty-three million, two hundred fifty-four thousand, one hundred fifty-five".

Divisors: 1 5 7 35 15155235833 75776179165 106086650831 530433254155