5304414643 has 8 divisors (see below), whose sum is σ = 5801906880. Its totient is φ = 4809467880.

The previous prime is 5304414641. The next prime is 5304414659. The reversal of 5304414643 is 3464144035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5304414643 - 2¹ = 5304414641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5304414599 and 5304414608.

It is not an unprimeable number, because it can be changed into a prime (5304414641) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 632005 + ... + 640342.

It is an arithmetic number, because the mean of its divisors is an integer number (725238360).

Almost surely, 2^5304414643 is an apocalyptic number.

5304414643 is a deficient number, since it is larger than the sum of its proper divisors (497492237).

5304414643 is a wasteful number, since it uses less digits than its factorization.

5304414643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1272737.

The product of its (nonzero) digits is 69120, while the sum is 34.

The square root of 5304414643 is about 72831.4124742889. The cubic root of 5304414643 is about 1743.9973542933.

Adding to 5304414643 its reverse (3464144035), we get a palindrome (8768558678).

The spelling of 5304414643 in words is "five billion, three hundred four million, four hundred fourteen thousand, six hundred forty-three".