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5304415351 is a prime number
BaseRepresentation
bin1001111000010101…
…01111010001110111
3111200200012012220211
410330022233101313
541330412242401
62234204010251
7245306533534
oct47412572167
914620165824
105304415351
112282227844
121040530987
13666c44311
143846a3d8b
15210a38951
hex13c2af477

5304415351 has 2 divisors, whose sum is σ = 5304415352. Its totient is φ = 5304415350.

The previous prime is 5304415343. The next prime is 5304415357. The reversal of 5304415351 is 1535144035.

5304415351 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5304415351 - 23 = 5304415343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5304415357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652207675 + 2652207676.

It is an arithmetic number, because the mean of its divisors is an integer number (2652207676).

Almost surely, 25304415351 is an apocalyptic number.

5304415351 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304415351 is an equidigital number, since it uses as much as digits as its factorization.

5304415351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 31.

The square root of 5304415351 is about 72831.4173348288. The cubic root of 5304415351 is about 1743.9974318859.

Adding to 5304415351 its reverse (1535144035), we get a palindrome (6839559386).

The spelling of 5304415351 in words is "five billion, three hundred four million, four hundred fifteen thousand, three hundred fifty-one".