Base | Representation |
---|---|
bin | 110001011001101011… |
… | …110000110101011111 |
3 | 12001220202010012021220 |
4 | 301121223300311133 |
5 | 1332113312030444 |
6 | 40211310224423 |
7 | 3555325463004 |
oct | 613153606537 |
9 | 161822105256 |
10 | 53044251999 |
11 | 205501086a2 |
12 | a3444b5113 |
13 | 500467927b |
14 | 27d2b758ab |
15 | 15a6c7a619 |
hex | c59af0d5f |
53044251999 has 4 divisors (see below), whose sum is σ = 70725669336. Its totient is φ = 35362834664.
The previous prime is 53044251991. The next prime is 53044252007. The reversal of 53044251999 is 99915244035.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (53044251991) and next prime (53044252007).
It is a cyclic number.
It is not a de Polignac number, because 53044251999 - 23 = 53044251991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53044251991) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8840708664 + ... + 8840708669.
It is an arithmetic number, because the mean of its divisors is an integer number (17681417334).
Almost surely, 253044251999 is an apocalyptic number.
53044251999 is a deficient number, since it is larger than the sum of its proper divisors (17681417337).
53044251999 is a wasteful number, since it uses less digits than its factorization.
53044251999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17681417336.
The product of its (nonzero) digits is 1749600, while the sum is 51.
The spelling of 53044251999 in words is "fifty-three billion, forty-four million, two hundred fifty-one thousand, nine hundred ninety-nine".
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