Base | Representation |
---|---|
bin | 100110100110000100011… |
… | …0011111001111101011011 |
3 | 200210002200000110011221212 |
4 | 1031030020303321331123 |
5 | 1143401434200410120 |
6 | 15140453404053335 |
7 | 1055142531522566 |
oct | 115141063717533 |
9 | 20702600404855 |
10 | 5304432435035 |
11 | 1765662906908 |
12 | 71804b83424b |
13 | 2c628a2a12a6 |
14 | 144a434474dd |
15 | 92ea90c46c5 |
hex | 4d308cf9f5b |
5304432435035 has 32 divisors (see below), whose sum is σ = 6778002369600. Its totient is φ = 3971302686720.
The previous prime is 5304432435013. The next prime is 5304432435067. The reversal of 5304432435035 is 5305342344035.
It is not a de Polignac number, because 5304432435035 - 28 = 5304432434779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5304432434983 and 5304432435001.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14791400 + ... + 15145770.
It is an arithmetic number, because the mean of its divisors is an integer number (211812574050).
Almost surely, 25304432435035 is an apocalyptic number.
5304432435035 is a deficient number, since it is larger than the sum of its proper divisors (1473569934565).
5304432435035 is a wasteful number, since it uses less digits than its factorization.
5304432435035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 355391.
The product of its (nonzero) digits is 1296000, while the sum is 41.
The spelling of 5304432435035 in words is "five trillion, three hundred four billion, four hundred thirty-two million, four hundred thirty-five thousand, thirty-five".
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