Base | Representation |
---|---|
bin | 11000000111110010110010… |
… | …00111101110101110010111 |
3 | 20221210222201100102011220110 |
4 | 30003321121013232232113 |
5 | 23423034302333213330 |
6 | 304452122312534103 |
7 | 14113220140511502 |
oct | 1403713107565627 |
9 | 227728640364813 |
10 | 53044341304215 |
11 | 159a0a84891a28 |
12 | 5b484226b1333 |
13 | 237a0a1856ca1 |
14 | d155074a8139 |
15 | 61ec1207cdb0 |
hex | 303e591eeb97 |
53044341304215 has 16 divisors (see below), whose sum is σ = 84972103372800. Its totient is φ = 28256596266912.
The previous prime is 53044341304211. The next prime is 53044341304243. The reversal of 53044341304215 is 51240314344035.
It is not a de Polignac number, because 53044341304215 - 22 = 53044341304211 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53044341304211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2107430455 + ... + 2107455624.
It is an arithmetic number, because the mean of its divisors is an integer number (5310756460800).
Almost surely, 253044341304215 is an apocalyptic number.
53044341304215 is a deficient number, since it is larger than the sum of its proper divisors (31927762068585).
53044341304215 is a wasteful number, since it uses less digits than its factorization.
53044341304215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4214886926.
The product of its (nonzero) digits is 345600, while the sum is 39.
The spelling of 53044341304215 in words is "fifty-three trillion, forty-four billion, three hundred forty-one million, three hundred four thousand, two hundred fifteen".
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