Base | Representation |
---|---|
bin | 100110100110000110011… |
… | …0101101001101001110101 |
3 | 200210002211201120220120201 |
4 | 1031030030311221221311 |
5 | 1143402104000021042 |
6 | 15140504220200501 |
7 | 1055144312032222 |
oct | 115141465515165 |
9 | 20702751526521 |
10 | 5304500001397 |
11 | 1765697a65483 |
12 | 71806a399131 |
13 | 2c629b29a19c |
14 | 144a4c3d4949 |
15 | 92eaeebe1b7 |
hex | 4d30cd69a75 |
5304500001397 has 2 divisors, whose sum is σ = 5304500001398. Its totient is φ = 5304500001396.
The previous prime is 5304500001341. The next prime is 5304500001523. The reversal of 5304500001397 is 7931000054035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3515002527556 + 1789497473841 = 1874834^2 + 1337721^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5304500001397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5304500005397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652250000698 + 2652250000699.
It is an arithmetic number, because the mean of its divisors is an integer number (2652250000699).
Almost surely, 25304500001397 is an apocalyptic number.
It is an amenable number.
5304500001397 is a deficient number, since it is larger than the sum of its proper divisors (1).
5304500001397 is an equidigital number, since it uses as much as digits as its factorization.
5304500001397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 5304500001397 in words is "five trillion, three hundred four billion, five hundred million, one thousand, three hundred ninety-seven".
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