Base | Representation |
---|---|
bin | 1111011100000010100… |
… | …11000101011011011111 |
3 | 1212201011222201020111101 |
4 | 13232001103011123133 |
5 | 32142330230204442 |
6 | 1043404021333531 |
7 | 53216023441033 |
oct | 7560123053337 |
9 | 1781158636441 |
10 | 530450241247 |
11 | 194a65372433 |
12 | 8697a8672a7 |
13 | 3b0378955c4 |
14 | 1b9613901c3 |
15 | dbe9046cb7 |
hex | 7b814c56df |
530450241247 has 2 divisors, whose sum is σ = 530450241248. Its totient is φ = 530450241246.
The previous prime is 530450241221. The next prime is 530450241263. The reversal of 530450241247 is 742142054035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530450241247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530850241247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265225120623 + 265225120624.
It is an arithmetic number, because the mean of its divisors is an integer number (265225120624).
Almost surely, 2530450241247 is an apocalyptic number.
530450241247 is a deficient number, since it is larger than the sum of its proper divisors (1).
530450241247 is an equidigital number, since it uses as much as digits as its factorization.
530450241247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 37.
The spelling of 530450241247 in words is "five hundred thirty billion, four hundred fifty million, two hundred forty-one thousand, two hundred forty-seven".
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