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5304533340021 = 31768177780007
BaseRepresentation
bin100110100110000111011…
…0100110100111101110101
3200210002221001022200120120
41031030032310310331311
51143402141013340041
615140511410522153
71055145165304326
oct115141664647565
920702831280516
105304533340021
111765704866263
12718079596359
132c62a5170996
14144a529d244d
1592eb2da7366
hex4d30ed34f75

5304533340021 has 4 divisors (see below), whose sum is σ = 7072711120032. Its totient is φ = 3536355560012.

The previous prime is 5304533339977. The next prime is 5304533340059. The reversal of 5304533340021 is 1200433354035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5304533340021 - 26 = 5304533339957 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5304533340061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 884088890001 + ... + 884088890006.

It is an arithmetic number, because the mean of its divisors is an integer number (1768177780008).

Almost surely, 25304533340021 is an apocalyptic number.

It is an amenable number.

5304533340021 is a deficient number, since it is larger than the sum of its proper divisors (1768177780011).

5304533340021 is a wasteful number, since it uses less digits than its factorization.

5304533340021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1768177780010.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 5304533340021 its reverse (1200433354035), we get a palindrome (6504966694056).

The spelling of 5304533340021 in words is "five trillion, three hundred four billion, five hundred thirty-three million, three hundred forty thousand, twenty-one".

Divisors: 1 3 1768177780007 5304533340021