Base | Representation |
---|---|
bin | 110001011001110000… |
… | …110100011010110001 |
3 | 12001220211121112101120 |
4 | 301121300310122301 |
5 | 1332114131434033 |
6 | 40211354452453 |
7 | 3555342653064 |
oct | 613160643261 |
9 | 161824545346 |
10 | 53045577393 |
11 | 20550933466 |
12 | a344a34129 |
13 | 5004a21623 |
14 | 27d2ddc8db |
15 | 15a6e3d1b3 |
hex | c59c346b1 |
53045577393 has 4 divisors (see below), whose sum is σ = 70727436528. Its totient is φ = 35363718260.
The previous prime is 53045577391. The next prime is 53045577433. The reversal of 53045577393 is 39377554035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53045577393 - 21 = 53045577391 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53045577391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8840929563 + ... + 8840929568.
It is an arithmetic number, because the mean of its divisors is an integer number (17681859132).
Almost surely, 253045577393 is an apocalyptic number.
It is an amenable number.
53045577393 is a deficient number, since it is larger than the sum of its proper divisors (17681859135).
53045577393 is a wasteful number, since it uses less digits than its factorization.
53045577393 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17681859134.
The product of its (nonzero) digits is 5953500, while the sum is 51.
The spelling of 53045577393 in words is "fifty-three billion, forty-five million, five hundred seventy-seven thousand, three hundred ninety-three".
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