Base | Representation |
---|---|
bin | 1111011100000101101… |
… | …11010001110101101001 |
3 | 1212201020211010122121112 |
4 | 13232002313101311221 |
5 | 32142403441201343 |
6 | 1043410400320105 |
7 | 53216462623034 |
oct | 7560267216551 |
9 | 1781224118545 |
10 | 530476506473 |
11 | 194a79181931 |
12 | 86987613035 |
13 | 3b040160664 |
14 | 1b964a6a01b |
15 | dbeb4d4218 |
hex | 7b82dd1d69 |
530476506473 has 4 divisors (see below), whose sum is σ = 537191399040. Its totient is φ = 523761613908.
The previous prime is 530476506419. The next prime is 530476506559. The reversal of 530476506473 is 374605674035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 374605674035 = 5 ⋅74921134807.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530476506473 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530476506403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3357446165 + ... + 3357446322.
It is an arithmetic number, because the mean of its divisors is an integer number (134297849760).
Almost surely, 2530476506473 is an apocalyptic number.
It is an amenable number.
530476506473 is a deficient number, since it is larger than the sum of its proper divisors (6714892567).
530476506473 is an equidigital number, since it uses as much as digits as its factorization.
530476506473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6714892566.
The product of its (nonzero) digits is 6350400, while the sum is 50.
The spelling of 530476506473 in words is "five hundred thirty billion, four hundred seventy-six million, five hundred six thousand, four hundred seventy-three".
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