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53050050545 = 510610010109
BaseRepresentation
bin110001011010000001…
…111000011111110001
312001221011000210101212
4301122001320133301
51332121303104140
640212034405505
73555425663252
oct613201703761
9161834023355
1053050050545
1120553409188
12a346430895
13500592966b
1427d3844b29
1515a7523765
hexc5a0787f1

53050050545 has 4 divisors (see below), whose sum is σ = 63660060660. Its totient is φ = 42440040432.

The previous prime is 53050050517. The next prime is 53050050563. The reversal of 53050050545 is 54505005035.

53050050545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20352731569 + 32697318976 = 142663^2 + 180824^2 .

It is a cyclic number.

It is not a de Polignac number, because 53050050545 - 214 = 53050034161 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5305005050 + ... + 5305005059.

It is an arithmetic number, because the mean of its divisors is an integer number (15915015165).

Almost surely, 253050050545 is an apocalyptic number.

It is an amenable number.

53050050545 is a deficient number, since it is larger than the sum of its proper divisors (10610010115).

53050050545 is a wasteful number, since it uses less digits than its factorization.

53050050545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10610010114.

The product of its (nonzero) digits is 37500, while the sum is 32.

The spelling of 53050050545 in words is "fifty-three billion, fifty million, fifty thousand, five hundred forty-five".

Divisors: 1 5 10610010109 53050050545