Base | Representation |
---|---|
bin | 110001011010000010… |
… | …000101001001010001 |
3 | 12001221011010102110200 |
4 | 301122002011021101 |
5 | 1332121311233403 |
6 | 40212035445413 |
7 | 3555426300303 |
oct | 613202051121 |
9 | 161834112420 |
10 | 53050102353 |
11 | 205534440a6 |
12 | a346456869 |
13 | 5005947111 |
14 | 27d3859973 |
15 | 15a7533ca3 |
hex | c5a085251 |
53050102353 has 6 divisors (see below), whose sum is σ = 76627925634. Its totient is φ = 35366734896.
The previous prime is 53050102351. The next prime is 53050102367. The reversal of 53050102353 is 35320105035.
53050102353 is a `hidden beast` number, since 5 + 305 + 0 + 1 + 0 + 2 + 353 = 666.
It can be written as a sum of positive squares in only one way, i.e., 32161759569 + 20888342784 = 179337^2 + 144528^2 .
It is not a de Polignac number, because 53050102353 - 21 = 53050102351 is a prime.
It is a super-2 number, since 2×530501023532 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53050102351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2947227900 + ... + 2947227917.
It is an arithmetic number, because the mean of its divisors is an integer number (12771320939).
Almost surely, 253050102353 is an apocalyptic number.
It is an amenable number.
53050102353 is a deficient number, since it is larger than the sum of its proper divisors (23577823281).
53050102353 is a wasteful number, since it uses less digits than its factorization.
53050102353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5894455823 (or 5894455820 counting only the distinct ones).
The product of its (nonzero) digits is 6750, while the sum is 27.
Adding to 53050102353 its reverse (35320105035), we get a palindrome (88370207388).
It can be divided in two parts, 53050 and 102353, that added together give a triangular number (155403 = T557).
The spelling of 53050102353 in words is "fifty-three billion, fifty million, one hundred two thousand, three hundred fifty-three".
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