53050401300043 has 32 divisors (see below), whose sum is σ = 65155194353664. Its totient is φ = 42157160128512.

The previous prime is 53050401300019. The next prime is 53050401300049. The reversal of 53050401300043 is 34000310405035.

53050401300043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53050401300043 - 2⁹ = 53050401299531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53050401299984 and 53050401300020.

It is not an unprimeable number, because it can be changed into a prime (53050401300049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 574384555 + ... + 574476907.

It is an arithmetic number, because the mean of its divisors is an integer number (2036099823552).

Almost surely, 2^{53050401300043} is an apocalyptic number.

53050401300043 is a deficient number, since it is larger than the sum of its proper divisors (12104793053621).

53050401300043 is a wasteful number, since it uses less digits than its factorization.

53050401300043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164491.

The product of its (nonzero) digits is 10800, while the sum is 28.

Adding to 53050401300043 its reverse (34000310405035), we get a palindrome (87050711705078).

The spelling of 53050401300043 in words is "fifty-three trillion, fifty billion, four hundred one million, three hundred thousand, forty-three".