Base | Representation |
---|---|
bin | 1111011100001010110… |
… | …01111001000010100101 |
3 | 1212201100210100101002122 |
4 | 13232011121321002211 |
5 | 32143000344244443 |
6 | 1043414522115325 |
7 | 53220521144444 |
oct | 7560531710245 |
9 | 1781323311078 |
10 | 530519134373 |
11 | 194aa02478a8 |
12 | 8699994bb45 |
13 | 3b048c37377 |
14 | 1b96a5a4d5b |
15 | dc00104968 |
hex | 7b856790a5 |
530519134373 has 2 divisors, whose sum is σ = 530519134374. Its totient is φ = 530519134372.
The previous prime is 530519134363. The next prime is 530519134423. The reversal of 530519134373 is 373431915035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 277583567044 + 252935567329 = 526862^2 + 502927^2 .
It is a cyclic number.
It is not a de Polignac number, because 530519134373 - 26 = 530519134309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530519134363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265259567186 + 265259567187.
It is an arithmetic number, because the mean of its divisors is an integer number (265259567187).
Almost surely, 2530519134373 is an apocalyptic number.
It is an amenable number.
530519134373 is a deficient number, since it is larger than the sum of its proper divisors (1).
530519134373 is an equidigital number, since it uses as much as digits as its factorization.
530519134373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 510300, while the sum is 44.
The spelling of 530519134373 in words is "five hundred thirty billion, five hundred nineteen million, one hundred thirty-four thousand, three hundred seventy-three".
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