Base | Representation |
---|---|
bin | 100110100110011100111… |
… | …0111101001101110011111 |
3 | 200210011210101012020210111 |
4 | 1031030321313221232133 |
5 | 1143410130402010303 |
6 | 15141111205150451 |
7 | 1055202114464134 |
oct | 115147167515637 |
9 | 20704711166714 |
10 | 5305255500703 |
11 | 1765a45471274 |
12 | 71823b3bb427 |
13 | 2c638b96bab2 |
14 | 144ac089858b |
15 | 930064a5b6d |
hex | 4d339de9b9f |
5305255500703 has 2 divisors, whose sum is σ = 5305255500704. Its totient is φ = 5305255500702.
The previous prime is 5305255500647. The next prime is 5305255500767. The reversal of 5305255500703 is 3070055525035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5305255500703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5305255500803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652627750351 + 2652627750352.
It is an arithmetic number, because the mean of its divisors is an integer number (2652627750352).
Almost surely, 25305255500703 is an apocalyptic number.
5305255500703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305255500703 is an equidigital number, since it uses as much as digits as its factorization.
5305255500703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 393750, while the sum is 40.
The spelling of 5305255500703 in words is "five trillion, three hundred five billion, two hundred fifty-five million, five hundred thousand, seven hundred three".
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