Base | Representation |
---|---|
bin | 1100101001100… |
… | …0100010100111 |
3 | 10200211101212102 |
4 | 3022120202213 |
5 | 102040203412 |
6 | 5133042315 |
7 | 1212643145 |
oct | 312304247 |
9 | 120741772 |
10 | 53053607 |
11 | 27a46a62 |
12 | 1592639b |
13 | acb7289 |
14 | 7090595 |
15 | 49ce8c2 |
hex | 32988a7 |
53053607 has 2 divisors, whose sum is σ = 53053608. Its totient is φ = 53053606.
The previous prime is 53053603. The next prime is 53053633. The reversal of 53053607 is 70635035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53053607 - 22 = 53053603 is a prime.
It is a Chen prime.
It is equal to p3173069 and since 53053607 and 3173069 have the same sum of digits, it is a Honaker prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53053607.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53053601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26526803 + 26526804.
It is an arithmetic number, because the mean of its divisors is an integer number (26526804).
Almost surely, 253053607 is an apocalyptic number.
53053607 is a deficient number, since it is larger than the sum of its proper divisors (1).
53053607 is an equidigital number, since it uses as much as digits as its factorization.
53053607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9450, while the sum is 29.
The square root of 53053607 is about 7283.7907026493. The cubic root of 53053607 is about 375.7551762767.
The spelling of 53053607 in words is "fifty-three million, fifty-three thousand, six hundred seven".
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