Base | Representation |
---|---|
bin | 1111011100001101011… |
… | …11011001100110100111 |
3 | 1212201102100112012112201 |
4 | 13232012233121212213 |
5 | 32143022114044431 |
6 | 1043421042355331 |
7 | 53221212524215 |
oct | 7560657314647 |
9 | 1781370465481 |
10 | 530541549991 |
11 | 195001968002 |
12 | 869a535bb47 |
13 | 3b05078514b |
14 | 1b96d55bcb5 |
15 | dc02081461 |
hex | 7b86bd99a7 |
530541549991 has 2 divisors, whose sum is σ = 530541549992. Its totient is φ = 530541549990.
The previous prime is 530541549971. The next prime is 530541550031. The reversal of 530541549991 is 199945145035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530541549991 - 25 = 530541549959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530541549931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265270774995 + 265270774996.
It is an arithmetic number, because the mean of its divisors is an integer number (265270774996).
Almost surely, 2530541549991 is an apocalyptic number.
530541549991 is a deficient number, since it is larger than the sum of its proper divisors (1).
530541549991 is an equidigital number, since it uses as much as digits as its factorization.
530541549991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374000, while the sum is 55.
The spelling of 530541549991 in words is "five hundred thirty billion, five hundred forty-one million, five hundred forty-nine thousand, nine hundred ninety-one".
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