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53054600311 = 148213579691
BaseRepresentation
bin110001011010010011…
…001111010001110111
312001221110120221111201
4301122103033101313
51332123434202221
640212320113331
73555512443006
oct613223172167
9161843527451
1053054600311
1120555a36519
12a347a65847
13500686052b
1427d42aac3d
1515a7b21891
hexc5a4cf477

53054600311 has 4 divisors (see below), whose sum is σ = 53058194824. Its totient is φ = 53051005800.

The previous prime is 53054600299. The next prime is 53054600317. The reversal of 53054600311 is 11300645035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53054600311 - 25 = 53054600279 is a prime.

It is a super-2 number, since 2×530546003112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53054600311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53054600317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1775025 + ... + 1804666.

It is an arithmetic number, because the mean of its divisors is an integer number (13264548706).

Almost surely, 253054600311 is an apocalyptic number.

53054600311 is a deficient number, since it is larger than the sum of its proper divisors (3594513).

53054600311 is a wasteful number, since it uses less digits than its factorization.

53054600311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3594512.

The product of its (nonzero) digits is 5400, while the sum is 28.

The spelling of 53054600311 in words is "fifty-three billion, fifty-four million, six hundred thousand, three hundred eleven".

Divisors: 1 14821 3579691 53054600311