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530554150200133 is a prime number
BaseRepresentation
bin111100010100010010100001…
…1101010000010001101000101
32120120112110222221122022002001
41320220211003222002031011
51024020044344422401013
65120221113430545301
7216516162302465203
oct17050450352021505
92516473887568061
10530554150200133
1114406182a2a7134
124b608b47508231
1319a07070781137
149502d5a60c073
154150de71e3ddd
hex1e28943a82345

530554150200133 has 2 divisors, whose sum is σ = 530554150200134. Its totient is φ = 530554150200132.

The previous prime is 530554150200031. The next prime is 530554150200143. The reversal of 530554150200133 is 331002051455035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 285378618281409 + 245175531918724 = 16893153^2 + 15658082^2 .

It is a cyclic number.

It is not a de Polignac number, because 530554150200133 - 229 = 530553613329221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530554150200092 and 530554150200101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530554150200143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265277075100066 + 265277075100067.

It is an arithmetic number, because the mean of its divisors is an integer number (265277075100067).

Almost surely, 2530554150200133 is an apocalyptic number.

It is an amenable number.

530554150200133 is a deficient number, since it is larger than the sum of its proper divisors (1).

530554150200133 is an equidigital number, since it uses as much as digits as its factorization.

530554150200133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 530554150200133 in words is "five hundred thirty trillion, five hundred fifty-four billion, one hundred fifty million, two hundred thousand, one hundred thirty-three".