Base | Representation |
---|---|
bin | 100110100110100101011… |
… | …1100111111011101001101 |
3 | 200210012112100111200002111 |
4 | 1031031022330333131031 |
5 | 1143411222240104401 |
6 | 15141155444224021 |
7 | 1055212164604606 |
oct | 115151274773515 |
9 | 20705470450074 |
10 | 5305542113101 |
11 | 176608223141a |
12 | 7182bb39b011 |
13 | 2c6406160129 |
14 | 144b0a984dad |
15 | 9302171ce51 |
hex | 4d34af3f74d |
5305542113101 has 8 divisors (see below), whose sum is σ = 5312500474464. Its totient is φ = 5298587034000.
The previous prime is 5305542113033. The next prime is 5305542113107. The reversal of 5305542113101 is 1013112455035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5305542113101 - 213 = 5305542104909 is a prime.
It is a super-2 number, since 2×53055421131012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5305542113107) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2422806 + ... + 4059688.
It is an arithmetic number, because the mean of its divisors is an integer number (664062559308).
Almost surely, 25305542113101 is an apocalyptic number.
It is an amenable number.
5305542113101 is a deficient number, since it is larger than the sum of its proper divisors (6958361363).
5305542113101 is a wasteful number, since it uses less digits than its factorization.
5305542113101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1641131.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 5305542113101 its reverse (1013112455035), we get a palindrome (6318654568136).
The spelling of 5305542113101 in words is "five trillion, three hundred five billion, five hundred forty-two million, one hundred thirteen thousand, one hundred one".
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