Base | Representation |
---|---|
bin | 11000001000000111101001… |
… | …01010000000000111100011 |
3 | 20221212001121212000222222102 |
4 | 30010003310222000013203 |
5 | 23423230221404111202 |
6 | 304501213502401015 |
7 | 14114064520650251 |
oct | 1404036452000743 |
9 | 227761555028872 |
10 | 53055540691427 |
11 | 159a580162433a |
12 | 5b4a62929016b |
13 | 237b167b82a21 |
14 | d15c8aa3b5d1 |
15 | 62016a3a4d02 |
hex | 3040f4a801e3 |
53055540691427 has 4 divisors (see below), whose sum is σ = 53056094077416. Its totient is φ = 53054987305440.
The previous prime is 53055540691381. The next prime is 53055540691459. The reversal of 53055540691427 is 72419604555035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53055540691427 - 28 = 53055540691171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53055540691487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276549158 + ... + 276740939.
It is an arithmetic number, because the mean of its divisors is an integer number (13264023519354).
Almost surely, 253055540691427 is an apocalyptic number.
53055540691427 is a deficient number, since it is larger than the sum of its proper divisors (553385989).
53055540691427 is an equidigital number, since it uses as much as digits as its factorization.
53055540691427 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 553385988.
The product of its (nonzero) digits is 22680000, while the sum is 56.
The spelling of 53055540691427 in words is "fifty-three trillion, fifty-five billion, five hundred forty million, six hundred ninety-one thousand, four hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •