Base | Representation |
---|---|
bin | 1111011100010100111… |
… | …01000000010110110101 |
3 | 1212201120200201201001112 |
4 | 13232022131000112311 |
5 | 32143134040234403 |
6 | 1043431145404405 |
7 | 53222600124446 |
oct | 7561235002665 |
9 | 1781520651045 |
10 | 530603836853 |
11 | 195034040052 |
12 | 86a02199705 |
13 | 3b060652c8c |
14 | 1b9779332cd |
15 | dc077869d8 |
hex | 7b8a7405b5 |
530603836853 has 2 divisors, whose sum is σ = 530603836854. Its totient is φ = 530603836852.
The previous prime is 530603836823. The next prime is 530603836879. The reversal of 530603836853 is 358638306035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 343462807249 + 187141029604 = 586057^2 + 432598^2 .
It is a cyclic number.
It is not a de Polignac number, because 530603836853 - 28 = 530603836597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530603836823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265301918426 + 265301918427.
It is an arithmetic number, because the mean of its divisors is an integer number (265301918427).
Almost surely, 2530603836853 is an apocalyptic number.
It is an amenable number.
530603836853 is a deficient number, since it is larger than the sum of its proper divisors (1).
530603836853 is an equidigital number, since it uses as much as digits as its factorization.
530603836853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4665600, while the sum is 50.
The spelling of 530603836853 in words is "five hundred thirty billion, six hundred three million, eight hundred thirty-six thousand, eight hundred fifty-three".
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