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5306063113147 is a prime number
BaseRepresentation
bin100110100110110101000…
…0000011100101110111011
3200210020212122212012210111
41031031222000130232323
51143413304124110042
615141323255125151
71055231122204306
oct115155200345673
920706778765714
105306063113147
11176631a331475
127184259737b7
132c648a088894
14144b59c45b3d
1593052333517
hex4d36a01cbbb

5306063113147 has 2 divisors, whose sum is σ = 5306063113148. Its totient is φ = 5306063113146.

The previous prime is 5306063112971. The next prime is 5306063113207. The reversal of 5306063113147 is 7413113606035.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5306063113147 - 211 = 5306063111099 is a prime.

It is not a weakly prime, because it can be changed into another prime (5306063111147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653031556573 + 2653031556574.

It is an arithmetic number, because the mean of its divisors is an integer number (2653031556574).

Almost surely, 25306063113147 is an apocalyptic number.

5306063113147 is a deficient number, since it is larger than the sum of its proper divisors (1).

5306063113147 is an equidigital number, since it uses as much as digits as its factorization.

5306063113147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 40.

The spelling of 5306063113147 in words is "five trillion, three hundred six billion, sixty-three million, one hundred thirteen thousand, one hundred forty-seven".