Base | Representation |
---|---|
bin | 111100010100101011101011… |
… | …1100110001000011000100111 |
3 | 2120120201122102210211112121001 |
4 | 1320221113113212020120213 |
5 | 1024021441013440444031 |
6 | 5120302010133334131 |
7 | 216523114066560061 |
oct | 17051272746103047 |
9 | 2516648383745531 |
10 | 530608171812391 |
11 | 144082731074a82 |
12 | 4b617503197347 |
13 | 19a0c19c76b78a |
14 | 95058030ba731 |
15 | 4152509b7c861 |
hex | 1e295d7988627 |
530608171812391 has 2 divisors, whose sum is σ = 530608171812392. Its totient is φ = 530608171812390.
The previous prime is 530608171812353. The next prime is 530608171812403. The reversal of 530608171812391 is 193218171806035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530608171812391 - 27 = 530608171812263 is a prime.
It is a super-2 number, since 2×5306081718123912 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530608171812311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265304085906195 + 265304085906196.
It is an arithmetic number, because the mean of its divisors is an integer number (265304085906196).
Almost surely, 2530608171812391 is an apocalyptic number.
530608171812391 is a deficient number, since it is larger than the sum of its proper divisors (1).
530608171812391 is an equidigital number, since it uses as much as digits as its factorization.
530608171812391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 55.
The spelling of 530608171812391 in words is "five hundred thirty trillion, six hundred eight billion, one hundred seventy-one million, eight hundred twelve thousand, three hundred ninety-one".
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