Base | Representation |
---|---|
bin | 110001011010110001… |
… | …011000010001101111 |
3 | 12001222000110100212212 |
4 | 301122301120101233 |
5 | 1332133000021422 |
6 | 40213201321035 |
7 | 3555636551342 |
oct | 613261302157 |
9 | 161860410785 |
10 | 53062501487 |
11 | 2055a442816 |
12 | a34a63617b |
13 | 5008398998 |
14 | 27d5366459 |
15 | 15a86829e2 |
hex | c5ac5846f |
53062501487 has 2 divisors, whose sum is σ = 53062501488. Its totient is φ = 53062501486.
The previous prime is 53062501483. The next prime is 53062501529. The reversal of 53062501487 is 78410526035.
53062501487 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53062501487 - 22 = 53062501483 is a prime.
It is a super-2 number, since 2×530625014872 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53062501483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26531250743 + 26531250744.
It is an arithmetic number, because the mean of its divisors is an integer number (26531250744).
Almost surely, 253062501487 is an apocalyptic number.
53062501487 is a deficient number, since it is larger than the sum of its proper divisors (1).
53062501487 is an equidigital number, since it uses as much as digits as its factorization.
53062501487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 53062501487 in words is "fifty-three billion, sixty-two million, five hundred one thousand, four hundred eighty-seven".
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