Base | Representation |
---|---|
bin | 111100010100110111111110… |
… | …1111011011011010110001110 |
3 | 2120120211011121120101221012111 |
4 | 1320221233331323123112032 |
5 | 1024022404112142424240 |
6 | 5120322055110054234 |
7 | 216525040451646526 |
oct | 17051577573332616 |
9 | 2516734546357174 |
10 | 530634584733070 |
11 | 144092955515244 |
12 | 4b62065494a37a |
13 | 19a1181b92881c |
14 | 9506bcad7a686 |
15 | 41530538e81ea |
hex | 1e29bfdedb58e |
530634584733070 has 16 divisors (see below), whose sum is σ = 955927085945328. Its totient is φ = 212079426465280.
The previous prime is 530634584733049. The next prime is 530634584733091. The reversal of 530634584733070 is 70337485436035.
It is an interprime number because it is at equal distance from previous prime (530634584733049) and next prime (530634584733091).
It is a junction number, because it is equal to n+sod(n) for n = 530634584732996 and 530634584733014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21800915716 + ... + 21800940055.
It is an arithmetic number, because the mean of its divisors is an integer number (59745442871583).
Almost surely, 2530634584733070 is an apocalyptic number.
530634584733070 is a deficient number, since it is larger than the sum of its proper divisors (425292501212258).
530634584733070 is a wasteful number, since it uses less digits than its factorization.
530634584733070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43601856995.
The product of its (nonzero) digits is 76204800, while the sum is 58.
The spelling of 530634584733070 in words is "five hundred thirty trillion, six hundred thirty-four billion, five hundred eighty-four million, seven hundred thirty-three thousand, seventy".
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