Base | Representation |
---|---|
bin | 100110100110111101100… |
… | …0000110111101001000011 |
3 | 200210021121112202010012212 |
4 | 1031031323000313221003 |
5 | 1143414400144423120 |
6 | 15141411450412335 |
7 | 1055241155334413 |
oct | 115157300675103 |
9 | 20707545663185 |
10 | 5306348436035 |
11 | 17664563a0809 |
12 | 7184a54310ab |
13 | 2c6504217caa |
14 | 144b85ab8643 |
15 | 9306c3e36c5 |
hex | 4d37b037a43 |
5306348436035 has 4 divisors (see below), whose sum is σ = 6367618123248. Its totient is φ = 4245078748824.
The previous prime is 5306348436029. The next prime is 5306348436061.
5306348436035 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5306348436035 is a prime.
It is a super-2 number, since 2×53063484360352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530634843599 + ... + 530634843608.
It is an arithmetic number, because the mean of its divisors is an integer number (1591904530812).
Almost surely, 25306348436035 is an apocalyptic number.
5306348436035 is a deficient number, since it is larger than the sum of its proper divisors (1061269687213).
5306348436035 is a wasteful number, since it uses less digits than its factorization.
5306348436035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1061269687212.
The product of its (nonzero) digits is 9331200, while the sum is 50.
The spelling of 5306348436035 in words is "five trillion, three hundred six billion, three hundred forty-eight million, four hundred thirty-six thousand, thirty-five".
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