Base | Representation |
---|---|
bin | 1111011100011010111… |
… | …01101011001000110011 |
3 | 1212201201012202201110122 |
4 | 13232031131223020303 |
5 | 32143240002444411 |
6 | 1043440152120455 |
7 | 53224052333021 |
oct | 7561535531063 |
9 | 1781635681418 |
10 | 530654343731 |
11 | 19505a5a7676 |
12 | 86a1709612b |
13 | 3b06ac57cc5 |
14 | 1b98051d711 |
15 | dc0be119db |
hex | 7b8d76b233 |
530654343731 has 2 divisors, whose sum is σ = 530654343732. Its totient is φ = 530654343730.
The previous prime is 530654343691. The next prime is 530654343781. The reversal of 530654343731 is 137343456035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530654343731 is a prime.
It is a super-2 number, since 2×5306543437312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530654343781) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265327171865 + 265327171866.
It is an arithmetic number, because the mean of its divisors is an integer number (265327171866).
Almost surely, 2530654343731 is an apocalyptic number.
530654343731 is a deficient number, since it is larger than the sum of its proper divisors (1).
530654343731 is an equidigital number, since it uses as much as digits as its factorization.
530654343731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1360800, while the sum is 44.
Adding to 530654343731 its reverse (137343456035), we get a palindrome (667997799766).
The spelling of 530654343731 in words is "five hundred thirty billion, six hundred fifty-four million, three hundred forty-three thousand, seven hundred thirty-one".
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