Base | Representation |
---|---|
bin | 11000001000011011011000… |
… | …00001000101011111010011 |
3 | 20221220001222001122110110210 |
4 | 30010031230001011133103 |
5 | 23423413420042303120 |
6 | 304510124532055203 |
7 | 14114621151336363 |
oct | 1404155401053723 |
9 | 227801861573423 |
10 | 53066133166035 |
11 | 159aa247817290 |
12 | 5b506a4764503 |
13 | 237c165532692 |
14 | d165b37489a3 |
15 | 62058a295ce0 |
hex | 30436c0457d3 |
53066133166035 has 48 divisors (see below), whose sum is σ = 94221040135680. Its totient is φ = 25292948662080.
The previous prime is 53066133166009. The next prime is 53066133166043.
53066133166035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53066133166035 - 210 = 53066133165011 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 45621115 + ... + 46769844.
It is an arithmetic number, because the mean of its divisors is an integer number (1962938336160).
Almost surely, 253066133166035 is an apocalyptic number.
53066133166035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53066133166035 is a deficient number, since it is larger than the sum of its proper divisors (41154906969645).
53066133166035 is a wasteful number, since it uses less digits than its factorization.
53066133166035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92391096 (or 92391037 counting only the distinct ones).
The product of its (nonzero) digits is 2624400, while the sum is 48.
The spelling of 53066133166035 in words is "fifty-three trillion, sixty-six billion, one hundred thirty-three million, one hundred sixty-six thousand, thirty-five".
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