Base | Representation |
---|---|
bin | 111100010101000111101100… |
… | …1010110001000010101001111 |
3 | 2120120221101201101102101222121 |
4 | 1320222033121112020111033 |
5 | 1024023432220130330242 |
6 | 5120345355435353411 |
7 | 216530343636032062 |
oct | 17052173126102517 |
9 | 2516841641371877 |
10 | 530668330714447 |
11 | 1440a61a2214552 |
12 | 4b6270b22b2867 |
13 | 19a14a690c3743 |
14 | 95086acad48d9 |
15 | 4153d7b31c667 |
hex | 1e2a3d958854f |
530668330714447 has 4 divisors (see below), whose sum is σ = 530757864773136. Its totient is φ = 530578796655760.
The previous prime is 530668330714439. The next prime is 530668330714513. The reversal of 530668330714447 is 744417033866035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530668330714447 - 23 = 530668330714439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530668330714147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44767020454 + ... + 44767032307.
It is an arithmetic number, because the mean of its divisors is an integer number (132689466193284).
Almost surely, 2530668330714447 is an apocalyptic number.
530668330714447 is a deficient number, since it is larger than the sum of its proper divisors (89534058689).
530668330714447 is an equidigital number, since it uses as much as digits as its factorization.
530668330714447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89534058688.
The product of its (nonzero) digits is 121927680, while the sum is 61.
The spelling of 530668330714447 in words is "five hundred thirty trillion, six hundred sixty-eight billion, three hundred thirty million, seven hundred fourteen thousand, four hundred forty-seven".
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