Base | Representation |
---|---|
bin | 11111101000010… |
… | …111101001111011 |
3 | 1100222120011002112 |
4 | 133220113221323 |
5 | 2041323120342 |
6 | 124354122535 |
7 | 16102450235 |
oct | 3750275173 |
9 | 1328504075 |
10 | 530676347 |
11 | 252609aa3 |
12 | 12988044b |
13 | 85c35b96 |
14 | 5069d255 |
15 | 318c7682 |
hex | 1fa17a7b |
530676347 has 4 divisors (see below), whose sum is σ = 537945960. Its totient is φ = 523406736.
The previous prime is 530676343. The next prime is 530676359. The reversal of 530676347 is 743676035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 743676035 = 5 ⋅148735207.
It is a cyclic number.
It is not a de Polignac number, because 530676347 - 22 = 530676343 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530676343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3634697 + ... + 3634842.
It is an arithmetic number, because the mean of its divisors is an integer number (134486490).
Almost surely, 2530676347 is an apocalyptic number.
530676347 is a deficient number, since it is larger than the sum of its proper divisors (7269613).
530676347 is an equidigital number, since it uses as much as digits as its factorization.
530676347 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7269612.
The product of its (nonzero) digits is 317520, while the sum is 41.
The square root of 530676347 is about 23036.4135012376. The cubic root of 530676347 is about 809.6113295592.
The spelling of 530676347 in words is "five hundred thirty million, six hundred seventy-six thousand, three hundred forty-seven".
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