Base | Representation |
---|---|
bin | 100110100111011000100… |
… | …0000101110100001010111 |
3 | 200210100221200102020201022 |
4 | 1031032301000232201113 |
5 | 1143423224104241333 |
6 | 15142041411551355 |
7 | 1055302465541444 |
oct | 115166100564127 |
9 | 20710850366638 |
10 | 5307254368343 |
11 | 17668808050a4 |
12 | 7186b88bb55b |
13 | 2c6619b0a905 |
14 | 144c3013a9cb |
15 | 930c1be2c98 |
hex | 4d3b102e857 |
5307254368343 has 4 divisors (see below), whose sum is σ = 5308904124240. Its totient is φ = 5305604612448.
The previous prime is 5307254368337. The next prime is 5307254368349. The reversal of 5307254368343 is 3438634527035.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (5307254368337) and next prime (5307254368349).
It is a cyclic number.
It is not a de Polignac number, because 5307254368343 - 240 = 4207742740567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5307254368349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 824873123 + ... + 824879556.
It is an arithmetic number, because the mean of its divisors is an integer number (1327226031060).
Almost surely, 25307254368343 is an apocalyptic number.
5307254368343 is a deficient number, since it is larger than the sum of its proper divisors (1649755897).
5307254368343 is a wasteful number, since it uses less digits than its factorization.
5307254368343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1649755896.
The product of its (nonzero) digits is 21772800, while the sum is 53.
The spelling of 5307254368343 in words is "five trillion, three hundred seven billion, two hundred fifty-four million, three hundred sixty-eight thousand, three hundred forty-three".
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