Base | Representation |
---|---|
bin | 100110100111101100111… |
… | …1001000001011110101101 |
3 | 200210102201110221212001021 |
4 | 1031033121321001132231 |
5 | 1143431130143332301 |
6 | 15142233432014141 |
7 | 1055325464253505 |
oct | 115173171013655 |
9 | 20712643855037 |
10 | 5307940214701 |
11 | 17670a2967673 |
12 | 71886a531351 |
13 | 2c66c8c32967 |
14 | 144c9726ca05 |
15 | 9311201b8a1 |
hex | 4d3d9e417ad |
5307940214701 has 2 divisors, whose sum is σ = 5307940214702. Its totient is φ = 5307940214700.
The previous prime is 5307940214651. The next prime is 5307940214719. The reversal of 5307940214701 is 1074120497035.
5307940214701 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3244195357225 + 2063744857476 = 1801165^2 + 1436574^2 .
It is a cyclic number.
It is not a de Polignac number, because 5307940214701 - 229 = 5307403343789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5307940214741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653970107350 + 2653970107351.
It is an arithmetic number, because the mean of its divisors is an integer number (2653970107351).
Almost surely, 25307940214701 is an apocalyptic number.
It is an amenable number.
5307940214701 is a deficient number, since it is larger than the sum of its proper divisors (1).
5307940214701 is an equidigital number, since it uses as much as digits as its factorization.
5307940214701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 5307940214701 in words is "five trillion, three hundred seven billion, nine hundred forty million, two hundred fourteen thousand, seven hundred one".
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