Base | Representation |
---|---|
bin | 100110101000000110000… |
… | …1100110111010001111111 |
3 | 200210111220022012122022100 |
4 | 1031100030030313101333 |
5 | 1143434342233322412 |
6 | 15142453303120143 |
7 | 1055355423543420 |
oct | 115201414672177 |
9 | 20714808178270 |
10 | 5308784276607 |
11 | 1767496362899 |
12 | 718a65143053 |
13 | 2c6801a72186 |
14 | 144d373c7647 |
15 | 93161198edc |
hex | 4d40c33747f |
5308784276607 has 48 divisors (see below), whose sum is σ = 9084259491840. Its totient is φ = 2923449580800.
The previous prime is 5308784276597. The next prime is 5308784276623. The reversal of 5308784276607 is 7066724878035.
5308784276607 is a `hidden beast` number, since 530 + 8 + 78 + 4 + 27 + 6 + 6 + 0 + 7 = 666.
It is not a de Polignac number, because 5308784276607 - 28 = 5308784276351 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5308784271607) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5219994 + ... + 6153527.
It is an arithmetic number, because the mean of its divisors is an integer number (189255406080).
Almost surely, 25308784276607 is an apocalyptic number.
5308784276607 is a deficient number, since it is larger than the sum of its proper divisors (3775475215233).
5308784276607 is a wasteful number, since it uses less digits than its factorization.
5308784276607 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11373804 (or 11373801 counting only the distinct ones).
The product of its (nonzero) digits is 94832640, while the sum is 63.
The spelling of 5308784276607 in words is "five trillion, three hundred eight billion, seven hundred eighty-four million, two hundred seventy-six thousand, six hundred seven".
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