Base | Representation |
---|---|
bin | 110001011100010100… |
… | …001001011110101011 |
3 | 12002000211011210112122 |
4 | 301130110021132223 |
5 | 1332211112040011 |
6 | 40215524301455 |
7 | 3556402616234 |
oct | 613424113653 |
9 | 162024153478 |
10 | 53088393131 |
11 | 20573017574 |
12 | a35724188b |
13 | 5010862997 |
14 | 27d898608b |
15 | 15aaa993db |
hex | c5c5097ab |
53088393131 has 2 divisors, whose sum is σ = 53088393132. Its totient is φ = 53088393130.
The previous prime is 53088393119. The next prime is 53088393143. The reversal of 53088393131 is 13139388035.
53088393131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (53088393119) and next prime (53088393143).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53088393131 is a prime.
It is a super-2 number, since 2×530883931312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53088393181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26544196565 + 26544196566.
It is an arithmetic number, because the mean of its divisors is an integer number (26544196566).
Almost surely, 253088393131 is an apocalyptic number.
53088393131 is a deficient number, since it is larger than the sum of its proper divisors (1).
53088393131 is an equidigital number, since it uses as much as digits as its factorization.
53088393131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 233280, while the sum is 44.
The spelling of 53088393131 in words is "fifty-three billion, eighty-eight million, three hundred ninety-three thousand, one hundred thirty-one".
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