Base | Representation |
---|---|
bin | 110001011100010100… |
… | …111100010101111111 |
3 | 12002000211120101022221 |
4 | 301130110330111333 |
5 | 1332211140221341 |
6 | 40215532550211 |
7 | 3556404444523 |
oct | 613424742577 |
9 | 162024511287 |
10 | 53088601471 |
11 | 2057314a054 |
12 | a357322367 |
13 | 5010906769 |
14 | 27d89dbd83 |
15 | 15aaadaed1 |
hex | c5c53c57f |
53088601471 has 2 divisors, whose sum is σ = 53088601472. Its totient is φ = 53088601470.
The previous prime is 53088601429. The next prime is 53088601481. The reversal of 53088601471 is 17410688035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53088601471 - 211 = 53088599423 is a prime.
It is a super-3 number, since 3×530886014713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53088601421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26544300735 + 26544300736.
It is an arithmetic number, because the mean of its divisors is an integer number (26544300736).
Almost surely, 253088601471 is an apocalyptic number.
53088601471 is a deficient number, since it is larger than the sum of its proper divisors (1).
53088601471 is an equidigital number, since it uses as much as digits as its factorization.
53088601471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 43.
The spelling of 53088601471 in words is "fifty-three billion, eighty-eight million, six hundred one thousand, four hundred seventy-one".
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