Base | Representation |
---|---|
bin | 1100101010001… |
… | …1011010100011 |
3 | 10200220122222001 |
4 | 3022203122203 |
5 | 102043120042 |
6 | 5134024431 |
7 | 1213220044 |
oct | 312433243 |
9 | 120818861 |
10 | 53098147 |
11 | 27a77473 |
12 | 15948117 |
13 | b00162b |
14 | 70a28cb |
15 | 49dcbb7 |
hex | 32a36a3 |
53098147 has 2 divisors, whose sum is σ = 53098148. Its totient is φ = 53098146.
The previous prime is 53098117. The next prime is 53098169. The reversal of 53098147 is 74189035.
53098147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53098147 is a prime.
It is not a weakly prime, because it can be changed into another prime (53098117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26549073 + 26549074.
It is an arithmetic number, because the mean of its divisors is an integer number (26549074).
Almost surely, 253098147 is an apocalyptic number.
53098147 is a deficient number, since it is larger than the sum of its proper divisors (1).
53098147 is an equidigital number, since it uses as much as digits as its factorization.
53098147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 37.
The square root of 53098147 is about 7286.8475351142. The cubic root of 53098147 is about 375.8602992218.
It can be divided in two parts, 5309 and 8147, that added together give a square (13456 = 1162).
The spelling of 53098147 in words is "fifty-three million, ninety-eight thousand, one hundred forty-seven".
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