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531000044 = 22132750011
BaseRepresentation
bin11111101001100…
…110101011101100
31101000011121010022
4133221212223230
52041414000134
6124405101312
716105266041
oct3751465354
91330147108
10531000044
11252810213
121299b7838
138601a313
14507451c8
153193d52e
hex1fa66aec

531000044 has 6 divisors (see below), whose sum is σ = 929250084. Its totient is φ = 265500020.

The previous prime is 531000013. The next prime is 531000079. The reversal of 531000044 is 440000135.

It is a super-2 number, since 2×5310000442 = 563922093456003872, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 530999986 and 531000031.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66375002 + ... + 66375009.

It is an arithmetic number, because the mean of its divisors is an integer number (154875014).

Almost surely, 2531000044 is an apocalyptic number.

It is an amenable number.

531000044 is a deficient number, since it is larger than the sum of its proper divisors (398250040).

531000044 is a wasteful number, since it uses less digits than its factorization.

531000044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132750015 (or 132750013 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 531000044 is about 23043.4381983245. The cubic root of 531000044 is about 809.7759091524.

Adding to 531000044 its reverse (440000135), we get a palindrome (971000179).

Subtracting from 531000044 its reverse (440000135), we obtain a palindrome (90999909).

The spelling of 531000044 in words is "five hundred thirty-one million, forty-four", and thus it is an aban number.

Divisors: 1 2 4 132750011 265500022 531000044