Base | Representation |
---|---|
bin | 1111011101000100010… |
… | …01101010110101000101 |
3 | 1212202121101212002010221 |
4 | 13232202021222311011 |
5 | 32144442330434000 |
6 | 1043534431144341 |
7 | 53235465415330 |
oct | 7564211526505 |
9 | 1782541762127 |
10 | 531001421125 |
11 | 195218505a9a |
12 | 86ab33750b1 |
13 | 3b0c4b29b46 |
14 | 1b9b4669617 |
15 | dc2c61e61a |
hex | 7ba226ad45 |
531001421125 has 16 divisors (see below), whose sum is σ = 757359742464. Its totient is φ = 364115259600.
The previous prime is 531001421101. The next prime is 531001421177. The reversal of 531001421125 is 521124100135.
It is not a de Polignac number, because 531001421125 - 231 = 528853937477 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 531001421125.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 303428509 + ... + 303430258.
It is an arithmetic number, because the mean of its divisors is an integer number (47334983904).
Almost surely, 2531001421125 is an apocalyptic number.
It is an amenable number.
531001421125 is a deficient number, since it is larger than the sum of its proper divisors (226358321339).
531001421125 is an equidigital number, since it uses as much as digits as its factorization.
531001421125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606858789 (or 606858779 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
The spelling of 531001421125 in words is "five hundred thirty-one billion, one million, four hundred twenty-one thousand, one hundred twenty-five".
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