Base | Representation |
---|---|
bin | 1111011101000101011… |
… | …00011101011001010101 |
3 | 1212202122001000102110022 |
4 | 13232202230131121111 |
5 | 32200002144304031 |
6 | 1043535354434525 |
7 | 53235636061313 |
oct | 7564254353125 |
9 | 1782561012408 |
10 | 531010541141 |
11 | 195222674aa3 |
12 | 86ab6432a45 |
13 | 3b0c69a0cc2 |
14 | 1b9b59610b3 |
15 | dc2d32197b |
hex | 7ba2b1d655 |
531010541141 has 4 divisors (see below), whose sum is σ = 536165983392. Its totient is φ = 525855098892.
The previous prime is 531010541107. The next prime is 531010541153. The reversal of 531010541141 is 141145010135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-531010541141 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 531010541141.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531010541741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2577720971 + ... + 2577721176.
It is an arithmetic number, because the mean of its divisors is an integer number (134041495848).
Almost surely, 2531010541141 is an apocalyptic number.
It is an amenable number.
531010541141 is a deficient number, since it is larger than the sum of its proper divisors (5155442251).
531010541141 is a wasteful number, since it uses less digits than its factorization.
531010541141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5155442250.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 531010541141 its reverse (141145010135), we get a palindrome (672155551276).
The spelling of 531010541141 in words is "five hundred thirty-one billion, ten million, five hundred forty-one thousand, one hundred forty-one".
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