Base | Representation |
---|---|
bin | 100110101000101101111… |
… | …1100110010000000110111 |
3 | 200210122100112211010022021 |
4 | 1031101123330302000313 |
5 | 1144000112243104012 |
6 | 15143234140214011 |
7 | 1055433531201466 |
oct | 115213374620067 |
9 | 20718315733267 |
10 | 5310122238007 |
11 | 1768012629014 |
12 | 71917923a307 |
13 | 2c698600bb02 |
14 | 145022d8a9dd |
15 | 931dd887007 |
hex | 4d45bf32037 |
5310122238007 has 2 divisors, whose sum is σ = 5310122238008. Its totient is φ = 5310122238006.
The previous prime is 5310122237957. The next prime is 5310122238013. The reversal of 5310122238007 is 7008322210135.
5310122238007 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5310122238007 - 223 = 5310113849399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5310122238307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655061119003 + 2655061119004.
It is an arithmetic number, because the mean of its divisors is an integer number (2655061119004).
Almost surely, 25310122238007 is an apocalyptic number.
5310122238007 is a deficient number, since it is larger than the sum of its proper divisors (1).
5310122238007 is an equidigital number, since it uses as much as digits as its factorization.
5310122238007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 5310122238007 in words is "five trillion, three hundred ten billion, one hundred twenty-two million, two hundred thirty-eight thousand, seven".
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