Base | Representation |
---|---|
bin | 110001011101001001… |
… | …010001111010011001 |
3 | 12002001210101102101221 |
4 | 301131021101322121 |
5 | 1332223143240210 |
6 | 40221143012041 |
7 | 3556632166165 |
oct | 613511217231 |
9 | 162053342357 |
10 | 53102321305 |
11 | 2057a96aa60 |
12 | a35ba3a021 |
13 | 50136cb4c7 |
14 | 27da76dca5 |
15 | 15abdeb1da |
hex | c5d251e99 |
53102321305 has 16 divisors (see below), whose sum is σ = 69522257088. Its totient is φ = 38616264000.
The previous prime is 53102321243. The next prime is 53102321347. The reversal of 53102321305 is 50312320135.
53102321305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53102321305 - 27 = 53102321177 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 53102321305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 644290 + ... + 722020.
It is an arithmetic number, because the mean of its divisors is an integer number (4345141068).
Almost surely, 253102321305 is an apocalyptic number.
53102321305 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
53102321305 is a deficient number, since it is larger than the sum of its proper divisors (16419935783).
53102321305 is a wasteful number, since it uses less digits than its factorization.
53102321305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90168.
The product of its (nonzero) digits is 2700, while the sum is 25.
The spelling of 53102321305 in words is "fifty-three billion, one hundred two million, three hundred twenty-one thousand, three hundred five".
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