Base | Representation |
---|---|
bin | 110001011101001100… |
… | …110010001110110001 |
3 | 12002001212010002202212 |
4 | 301131030302032301 |
5 | 1332223412140423 |
6 | 40221214421505 |
7 | 3556643044010 |
oct | 613514621661 |
9 | 162055102685 |
10 | 53103240113 |
11 | 20580438300 |
12 | a360201895 |
13 | 5013960791 |
14 | 27da92ca77 |
15 | 15ac02d578 |
hex | c5d3323b1 |
53103240113 has 24 divisors (see below), whose sum is σ = 66726180864. Its totient is φ = 41367997440.
The previous prime is 53103240107. The next prime is 53103240133. The reversal of 53103240113 is 31104230135.
53103240113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53103240113 - 24 = 53103240097 is a prime.
It is a super-2 number, since 2×531032401132 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53103240133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4655345 + ... + 4666737.
It is an arithmetic number, because the mean of its divisors is an integer number (2780257536).
Almost surely, 253103240113 is an apocalyptic number.
It is an amenable number.
53103240113 is a deficient number, since it is larger than the sum of its proper divisors (13622940751).
53103240113 is a wasteful number, since it uses less digits than its factorization.
53103240113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16925 (or 16914 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 53103240113 its reverse (31104230135), we get a palindrome (84207470248).
It can be divided in two parts, 5310 and 3240113, that added together give a palindrome (3245423).
The spelling of 53103240113 in words is "fifty-three billion, one hundred three million, two hundred forty thousand, one hundred thirteen".
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