Base | Representation |
---|---|
bin | 110001011101001111… |
… | …101011110000000011 |
3 | 12002001220112201010221 |
4 | 301131033223300003 |
5 | 1332224111000003 |
6 | 40221243003511 |
7 | 3556652360305 |
oct | 613517536003 |
9 | 162056481127 |
10 | 53104000003 |
11 | 2058090720a |
12 | a360509597 |
13 | 5013b68612 |
14 | 27daa89975 |
15 | 15ac12d7bd |
hex | c5d3ebc03 |
53104000003 has 2 divisors, whose sum is σ = 53104000004. Its totient is φ = 53104000002.
The previous prime is 53103999961. The next prime is 53104000009. The reversal of 53104000003 is 30000040135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53104000003 is a prime.
It is not a weakly prime, because it can be changed into another prime (53104000009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26552000001 + 26552000002.
It is an arithmetic number, because the mean of its divisors is an integer number (26552000002).
Almost surely, 253104000003 is an apocalyptic number.
53104000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
53104000003 is an equidigital number, since it uses as much as digits as its factorization.
53104000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 16.
Adding to 53104000003 its reverse (30000040135), we get a palindrome (83104040138).
The spelling of 53104000003 in words is "fifty-three billion, one hundred four million, three", and thus it is an aban number.
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