Base | Representation |
---|---|
bin | 110001011101001111… |
… | …101011101111011001 |
3 | 12002001220112201002101 |
4 | 301131033223233121 |
5 | 1332224110444321 |
6 | 40221243003401 |
7 | 3556652360215 |
oct | 613517535731 |
9 | 162056481071 |
10 | 53103999961 |
11 | 20580907181 |
12 | a360509561 |
13 | 5013b685ac |
14 | 27daa89945 |
15 | 15ac12d791 |
hex | c5d3ebbd9 |
53103999961 has 2 divisors, whose sum is σ = 53103999962. Its totient is φ = 53103999960.
The previous prime is 53103999947. The next prime is 53104000003. The reversal of 53103999961 is 16999930135.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33610255561 + 19493744400 = 183331^2 + 139620^2 .
It is a cyclic number.
It is not a de Polignac number, because 53103999961 - 29 = 53103999449 is a prime.
It is not a weakly prime, because it can be changed into another prime (53103999911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26551999980 + 26551999981.
It is an arithmetic number, because the mean of its divisors is an integer number (26551999981).
Almost surely, 253103999961 is an apocalyptic number.
It is an amenable number.
53103999961 is a deficient number, since it is larger than the sum of its proper divisors (1).
53103999961 is an equidigital number, since it uses as much as digits as its factorization.
53103999961 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1771470, while the sum is 55.
The spelling of 53103999961 in words is "fifty-three billion, one hundred three million, nine hundred ninety-nine thousand, nine hundred sixty-one".
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